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Moving Charges and Magnetism question

2019 · Q115
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Moving Charges and Magnetism question

2019 · Q115

NEETPhysicsMoving Charges and MagnetismMCQ+4 / −1
Ionized hydrogen atoms and α\alphaα-particles with same momenta enters perpendicular to a constant magnetic field, B. The ratio of their radii of their paths rH : rα\alphaα will be :
  1. A
    1 : 2
  2. B
    4 : 1
  3. C
    1 : 4
  4. D
    2 : 1
View written solutionFree

Correct answer: D

Radius of the path (r) = mvqB{{mv} \over {qB}}qBmv​ = pqB{p \over {qB}}qBp​

So, the radius for H-atom rH = peB{p \over {eB}}eBp​

The radius for α\alpha α particle rα\alpha α = p2eB{p \over {2eB}}2eBp​

∴\therefore∴ rHrα=peBp2eB{{{r_H}} \over {{r_\alpha }}} = {{{p \over {eB}}} \over {{p \over {2eB}}}}rα​rH​​=2eBp​eBp​​ = 21{2 \over 1}12​

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