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Moving Charges and Magnetism question

2016 · Q123
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Moving Charges and Magnetism question

2016 · Q123

NEETPhysicsMoving Charges and MagnetismMCQ+4 / −1
A long wire carrying a steady current is bent into a circular loop of one turn. The magnetic field at the centre of the loop is B. It is then bent into a circular coil of n turns. The magnetic field at the centre of this coil of n turns will be
  1. A
    nB
  2. B
    n2B
  3. C
    2nB
  4. D
    2n2B
View written solutionFree

Correct answer: B

For One turn loop :

B = μ0i2r{{{\mu _0}i} \over {2r}}2rμ0​i​

For n turn loop :

r = Rn{R \over n}nR​

B' = μ0ni2Rn{{{\mu _0}ni} \over {2{R \over n}}}2nR​μ0​ni​

= (μ0i2R)n2\left( {{{{\mu _0}i} \over {2R}}} \right){n^2}(2Rμ0​i​)n2

= n2B

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