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Moving Charges and Magnetism question

2016 · Q122
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Moving Charges and Magnetism question

2016 · Q122

NEETPhysicsMoving Charges and MagnetismMCQ+4 / −1
A long straight wire of radius aaa carries a steady current III. The current is uniformly distributed over its cross-section. The ratio of the magnetic fields B and B', at radial distance a2{a \over 2}2a​ and 2aaa respectively, from the axis of the wire is
  1. A
    1
  2. B
    4
  3. C
    14{1 \over 4}41​
  4. D
    12{1 \over 2}21​
View written solutionFree

Correct answer: A

For points inside the wire i.e., (r ≤\le≤ R)

Magnetic field B=μ0Ir2πR2B = {{{\mu _0}Ir} \over {2\pi {R^2}}}B=2πR2μ0​Ir​

For points outside the wire (r ≥\ge≥ R)

Magnetic field, B′=μ0I2πRB' = {{{\mu _0}I} \over {2\pi R}}B′=2πRμ0​I​

∴BB′=μ0I(a/2)2πa2μ0I2π(2a)=1:1 \therefore {B \over {B'}} = {{{{{\mu _0}I\left( {a/2} \right)} \over {2\pi {a^2}}}} \over {{{{\mu _0}I} \over {2\pi \left( {2a} \right)}}}} = 1:1∴B′B​=2π(2a)μ0​I​2πa2μ0​I(a/2)​​=1:1

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