NEETPhysicsMoving Charges and MagnetismMCQ+4 / −1
A metallic rod of mass per unit length
0.5 kg m–1 is lying horizontally on a smooth
inclined plane which makes an angle of 30° with
the horizontal. The rod is not allowed to slide
down by flowing a current through it when a
magnetic field of induction 0.25 T is acting on it
in the vertical direction. The current flowing in
the rod to keep it stationary is
- A7.14 A
- B5.98 A
- C14.76 A
- D11.32 A
View written solutionFree
Correct answer: D
Given Mass per unit length of a metallic rod is
= 0.5 kg m-1

From figure, for equilibrium
mg sin 30o = IB cos 30o
I =
= = 11.32 A
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