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Moving Charges and Magnetism question

2016 · Q124
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Moving Charges and Magnetism question

2016 · Q124

NEETPhysicsMoving Charges and MagnetismMCQ+4 / −1
An electron is moving in a circular path under the influence of a transverse magnetic field of 3.57 ×\times× 10-2 T. If the value of e/m is 1.76 ×\times× 1011 C kg−-−1, the frequency of revoluation of the electron is
  1. A
    1 GHz
  2. B
    100 MHz
  3. C
    62.8 MHz
  4. D
    6.28 MHz
View written solutionFree

Correct answer: A

Frequency of revolution of charge in magnetic field is given as

F = qB2πm{{qB} \over {2\pi m}}2πmqB​

= (1.76×1011)×3.57×10−22×3.14{{\left( {1.76 \times {{10}^{11}}} \right) \times 3.57 \times {{10}^{ - 2}}} \over {2 \times 3.14}}2×3.14(1.76×1011)×3.57×10−2​

= 109 Hz

= 1 GHz

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