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Moving Charges and Magnetism question

2018 · Q125
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Moving Charges and Magnetism question

2018 · Q125

NEETPhysicsMoving Charges and MagnetismMCQ+4 / −1
Current sensitivity of a moving coil galvanometer is 5 div/mA and its voltage sensitivity (angular deflection per unit voltage applied) is 20 div/V. The resistance of the galvanometer is
  1. A
    40 Ω\OmegaΩ
  2. B
    25 Ω\OmegaΩ
  3. C
    250 Ω\OmegaΩ
  4. D
    500 Ω\OmegaΩ
View written solutionFree

Correct answer: C

Current sensitivity of moving coil galvanometer

Is = NBAC{{NBA} \over C}CNBA​ .....(i)

Voltage sensitivity of moving coil galvanometer,

Vs = NBACRG{{NBA} \over {C{R_G}}}CRG​NBA​

Dividing eqn. (i) by (ii)

Resistance of galvanometer

RG = IsVS=5×120×10−3=500020=250 Ω{{{I_s}} \over {{V_S}}} = {{5 \times 1} \over {20 \times {{10}^{ - 3}}}} = {{5000} \over {20}} = 250\,\Omega VS​Is​​=20×10−35×1​=205000​=250Ω

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