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Moving Charges and Magnetism question

2017 · Q128
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Moving Charges and Magnetism question

2017 · Q128

NEETPhysicsMoving Charges and MagnetismMCQ+4 / −1
An arrangement of three parallel straight wires placed perpendicular to plane of paper carrying same current ′I′'I'′I′ along the same direction as shown in fogure. Magnitude of force per unit length on the middle wire ′B′'B'′B′ is given by

NEET 2017 Physics - Moving Charges and Magnetism Question 76 English
  1. A
    2μ0I2πd{{2{\mu _0}{I^2}} \over {\pi d}}πd2μ0​I2​
  2. B
    2μ0I2πd{{\sqrt 2 {\mu _0}{I^2}} \over {\pi d}}πd2​μ0​I2​
  3. C
    μ0I22πd{{{\mu _0}{I^2}} \over {\sqrt 2 \pi d}}2​πdμ0​I2​
  4. D
    μ0I22πd{{{\mu _0}{I^2}} \over {2\pi d}}2πdμ0​I2​
View written solutionFree

Correct answer: C

NEET 2017 Physics - Moving Charges and Magnetism Question 76 English Explanation


Since same current flowing through both the wires

ii = i2 = i

So F1 = $${{{\mu _0}{i^2}} \over {2\pi d}}$$ = F2

$ \therefore $ Magnitude of force per unit length on the middle wire 'B'

Fnet = $$\sqrt {F_1^2 + F_2^2} $$ = $${{{\mu _0}{i^2}} \over {\sqrt 2 \pi d}}$$
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