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Moving Charges and Magnetism question

2015 · Q121
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Moving Charges and Magnetism question

2015 · Q121

NEETPhysicsMoving Charges and MagnetismMCQ+4 / −1
A conducting square frame of side 'a' and a long straight wire carrying current III are located in the same plane as shown in the figure. The frame moves to the right with a constant velocity 'V'. The emf induced in the frame will be proportional to

AIPMT 2015 Cancelled Paper Physics - Moving Charges and Magnetism Question 68 English
  1. A
    1(2x+a)2{1 \over {{{\left( {2x + a} \right)}^2}}}(2x+a)21​
  2. B
    1(2x−a)(2x+a){1 \over {\left( {2x - a} \right)\left( {2x + a} \right)}}(2x−a)(2x+a)1​
  3. C
    1x2{1 \over {{x^2}}}x21​
  4. D
    1(2x−a)2{1 \over {{{\left( {2x - a} \right)}^2}}}(2x−a)21​
View written solutionFree

Correct answer: B

AIPMT 2015 Cancelled Paper Physics - Moving Charges and Magnetism Question 68 English Explanation

The emf in AD:

e1 = (a × μ0iv)/2π(x −a/2)

The emf in EF :

e2 = (a × μ0i × v)/2π(x + a/2)

Net emf = e1 – e2

⇒e=μ02πa×i×v[1x−a2−1x+a2] \Rightarrow e = {{{\mu _0}} \over {2\pi }}a \times i \times v\left[ {{1 \over {x - {a \over 2}}} - {1 \over {x + {a \over 2}}}} \right]⇒e=2πμ0​​a×i×v[x−2a​1​−x+2a​1​]

e∝1(2x−a)(2x+a)e \propto {1 \over {\left( {2x - a} \right)\left( {2x + a} \right)}}e∝(2x−a)(2x+a)1​

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