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Thermodynamics question

2023 · Shift 1 · Q12

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JEE Advanced
Chemistry
Thermodynamics
2023 · Shift 1 · Q12

Thermodynamics question

2023 · Shift 1 · Q12

JEE AdvancedChemistryThermodynamicsNumerical+4 / −1

In a one-litre flask, 6 moles of

A

undergoes the reaction

A(\mathrm{~g}) \rightleftharpoons P(\mathrm{~g})

. The progress of product formation at two temperatures (in Kelvin),

\mathrm{T}_1

and

\mathrm{T}_2

, is shown in the figure: JEE Advanced 2023 Paper 1 Online Chemistry - Thermodynamics Question 6 English

JEE Advanced 2023 Paper 1 Online Chemistry - Thermodynamics Question 6 English

If

\mathrm{T}_1=2 \mathrm{~T}_2

and

\left(\Delta \mathrm{G}_2^{\Theta}-\Delta \mathrm{G}_1^{\Theta}\right)=\mathrm{RT}_2 \ln \mathrm{x}

, then the value of

\mathrm{x}

is

\underline{\hspace{2cm}}

.

\left[\Delta \mathrm{G}_1^{\Theta}\right.

and

\Delta \mathrm{G}_2^{\Theta}

are standard Gibb's free energy change for the reaction at temperatures

\mathrm{T}_1

and

\mathrm{T}_2

, respectively.]

Numerical answer

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