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Thermodynamics question

2021 · Shift 2 · Q17
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Thermodynamics question

2021 · Shift 2 · Q17

JEE AdvancedChemistryThermodynamicsNumerical+4 / −1
One mole of an ideal gas at 900 K, undergoes two reversible processes, I followed by II, as shown below. If the work done by the gas in the two processes are same, the value of ln⁡V3V2\ln {{{V_3}} \over {{V_2}}}lnV2​V3​​ is ‾\underline{\hspace{2cm}}​. JEE Advanced 2021 Paper 2 Online Chemistry - Thermodynamics Question 19 English (U : internal energy, S : entropy, p : pressure, V : volume, R : gas constant) (Given : molar heat capacity at constant volume, CV,m of the gas is 52{5 \over 2}25​ R)
Numerical answer
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