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Thermodynamics question

2021 · Shift 1 · Q8
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  5. /2021 · Shift 1 · Q8

Thermodynamics question

2021 · Shift 1 · Q8

JEE AdvancedChemistryThermodynamicsNumerical+2 / −1
For the reaction, X(s) ⇌\rightleftharpoons⇌ Y(s) + Z(g), the plot of ln⁡pzpθ\ln {{pz} \over {{p^\theta }}}lnpθpz​ versus 104T{{{{10}^4}} \over T}T104​ is given below (in solid line), where pz is the pressure (in bar) of the gas Z at temperature T and pθ{{p^\theta }}pθ = 1 bar. JEE Advanced 2021 Paper 1 Online Chemistry - Thermodynamics Question 22 English Comprehension (Given, d(ln⁡K)d(1T)=−ΔHθR{{d(\ln K)} \over {d\left( {{1 \over T}} \right)}} = - {{\Delta {H^\theta }} \over R}d(T1​)d(lnK)​=−RΔHθ​, where the equilibrium constant, K=pzpθK = {{pz} \over {{p^\theta }}}K=pθpz​ and the gas constant, R = 8.314 J K −-− 1 mol −-− 1)The value of Δ\DeltaΔ S θ\thetaθ (in J K −-− 1 mol −-− 1) for the given reaction, at 1000 K is ‾\underline{\hspace{2cm}}​.
Numerical answer
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