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Thermodynamics question

2022 · Shift 2 · Q10
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Thermodynamics question

2022 · Shift 2 · Q10

JEE AdvancedChemistryThermodynamicsMultiple correct+4 / −2
The correct option(s) about entropy (S) is(are) [R=[\mathrm{R}=[R= gas constant, F=\mathrm{F}=F= Faraday constant, T=\mathrm{T}=T= Temperature ]]]
  1. A
    For the reaction, M(s)+2H+(aq)→H2(g)+M2+(aq)\mathrm{M}(s)+2 \mathrm{H}^{+}(a q) \rightarrow \mathrm{H}_{2}(g)+\mathrm{M}^{2+}(a q)M(s)+2H+(aq)→H2​(g)+M2+(aq), if dEcelldT=RF\frac{d E_\text{cell}}{d T}=\frac{R}{F}dTdEcell​​=FR​, then the entropy change of the reaction is R\mathrm{R}R (assume that entropy and internal energy changes are temperature independent).
  2. B
    The cell reaction, Pt⁡(s)∣H2(g,1\operatorname{Pt}(s) \mid \mathrm{H}_{2}(g, 1Pt(s)∣H2​(g,1 bar )∣H+(aq,0.01M)∥H+(aq,0.1M)∣H2(g,1bar)∣Pt⁡(s))\left|\mathrm{H}^{+}(a q, 0.01 \mathrm{M}) \| \mathrm{H}^{+}(a q, 0.1 \mathrm{M})\right| \mathrm{H}_{2}(g, 1 \mathrm{bar}) \mid \operatorname{Pt}(s))∣H+(aq,0.01M)∥H+(aq,0.1M)∣H2​(g,1bar)∣Pt(s), is an entropy driven process.
  3. C
    For racemization of an optically active compound, ΔS>0\Delta \mathrm{S}\gt 0ΔS>0.
  4. D
    ΔS>0\Delta \mathrm{S}\gt 0ΔS>0, for [Ni(H2O)6]2++3\left[\mathrm{Ni}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}+3[Ni(H2​O)6​]2++3 en →[Ni(en)3]2++6H2O\rightarrow\left[\mathrm{Ni}(\mathrm{en})_{3}\right]^{2+}+6 \mathrm{H}_{2} \mathrm{O}→[Ni(en)3​]2++6H2​O(where en === ethylenediamine).
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