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Thermodynamics question

2023 · Shift 2 · Q14

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JEE Advanced
Chemistry
Thermodynamics
2023 · Shift 2 · Q14

Thermodynamics question

2023 · Shift 2 · Q14

JEE AdvancedChemistryThermodynamicsNumerical+3 / −1

The entropy versus temperature plot for phases

\alpha

and

\beta

at 1 bar pressure is given.

S_{\mathrm{T}}

and

S_0

are entropies of the phases at temperatures

\mathrm{T}

and

0 \mathrm{~K}

, respectively. JEE Advanced 2023 Paper 2 Online Chemistry - Thermodynamics Question 5 English Comprehension

JEE Advanced 2023 Paper 2 Online Chemistry - Thermodynamics Question 5 English Comprehension

The transition temperature for

\alpha

to

\beta

phase change is

600 \mathrm{~K}

and

C_{\mathrm{p}, \beta}-C_{\mathrm{p}, \alpha}=1 \mathrm{~J} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}

. Assume

\left(C_{\mathrm{p}, \beta}-C_{\mathrm{p}, \alpha}\right)

is independent of temperature in the range of 200 to

700 \mathrm{~K} . C_{\mathrm{p}, \alpha}

and

C_{\mathrm{p}, \beta}

are heat capacities of

\alpha

and

\beta

phases, respectively.The value of entropy change,

S_\beta-S_\alpha

(in

\mathrm{J} \mathrm{mol}^{-1} \mathrm{~K}^{-1}

), at

300 \mathrm{~K}

is

\underline{\hspace{2cm}}

. [Use :

\ln 2=0.69

Given :

S_\beta-S_\alpha=0

at

0 \mathrm{~K}

]

Numerical answer

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