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Moving Charges and Magnetism question

2021 · Q142
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Moving Charges and Magnetism question

2021 · Q142

NEETPhysicsMoving Charges and MagnetismMCQ+4 / −1
An infinitely long straight conductor carries a current of 5A as shown. An electron is moving with a speed of 105 m/s parallel to the conductor. The perpendicular distance between the electron and the conductor is 20cm at an instant. Calculate the magnitude of the force experienced by the electron at that instant.

NEET 2021 Physics - Moving Charges and Magnetism Question 18 English
  1. A
    8 ×\times× 10−-−20 N
  2. B
    4 ×\times× 10−-−20 N
  3. C
    8π\piπ ×\times× 10−-−20 N
  4. D
    4π\piπ ×\times× 10−-−20 N
View written solutionFree

Correct answer: A

B=μ0I2πRB = {{{\mu _0}I} \over {2\pi R}}B=2πRμ0​I​

F = BVq sinθ\thetaθ

θ\thetaθ = 90∘^\circ∘

F = BVq

F=μ0I2πR×V×e=2×10−7×520×10−2×105×1.6×10−19F = {{{\mu _0}I} \over {2\pi R}} \times V \times e = {{2 \times {{10}^{ - 7}} \times 5} \over {20 \times {{10}^{ - 2}}}} \times {10^5} \times 1.6 \times {10^{ - 19}}F=2πRμ0​I​×V×e=20×10−22×10−7×5​×105×1.6×10−19

F = 8 ×\times× 10−-−20 N

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