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Heat and Thermodynamics question

2025 · 2 Apr · Shift 2 · Q65
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Heat and Thermodynamics question

2025 · 2 Apr · Shift 2 · Q65

JEE MainPhysicsHeat and ThermodynamicsMCQ+4 / −1
 Match List - I with List - II. \text { Match List - I with List - II. } Match List - I with List - II.   List - I List−II  (A)  Heat capacity of body  (I) J kg−1 (B)  Specific heat capacity of body  (II) J K−1 (C)  Latent heat  (III) J kg−1 K−1 (D)  Thermal conductivity  (IV) J m−1 K−1 s−1 Choose the correct answer from the options given below : \begin{array}{lll} & \text { List - I } & {List - II }\\ \text { } \\ \text { (A) } & \text { Heat capacity of body } & \text { (I) } \mathrm{J} \mathrm{~kg}^{-1} \\ \text { (B) } & \text { Specific heat capacity of body } & \text { (II) } \mathrm{J} \mathrm{~K}^{-1} \\ \text { (C) } & \text { Latent heat } & \text { (III) } \mathrm{J} \mathrm{~kg}^{-1} \mathrm{~K}^{-1} \\ \text { (D) } & \text { Thermal conductivity } & \text { (IV) } \mathrm{J} \mathrm{~m}^{-1} \mathrm{~K}^{-1} \mathrm{~s}^{-1} \end{array} \text { Choose the correct answer from the options given below : }  (A)  (B)  (C)  (D) ​ List - I  Heat capacity of body  Specific heat capacity of body  Latent heat  Thermal conductivity ​List−II (I) J kg−1 (II) J K−1 (III) J kg−1 K−1 (IV) J m−1 K−1 s−1​ Choose the correct answer from the options given below : 
  1. A
    (A)-(IV), (B)-(III), (C)-(II), (D)-(I)
  2. B
    (A)-(III), (B)-(I), (C)-(II), (D)-(IV)
  3. C
    (A)-(III), (B)-(IV), (C)-(I), (D)-(II)
  4. D
    (A)-(II), (B)-(III), (C)-(I), (D)-(IV)
View written solutionFree

Correct answer: D

  1. Match each physical quantity with its SI unit

    (A) Heat capacity of a body

    • Heat capacity is defined as C=dQdTC = \frac{dQ}{dT}C=dTdQ​
    • Its SI unit is energy per unit temperature: J K−1\mathrm{J\,K^{-1}}JK−1
    • So, (A) →\to→ (II)

    (B) Specific heat capacity of a body

    • Specific heat capacity is heat capacity per unit mass: c=1mdQdTc = \frac{1}{m}\frac{dQ}{dT}c=m1​dTdQ​
    • Its SI unit is J kg−1 K−1\mathrm{J\,kg^{-1}\,K^{-1}}Jkg−1K−1
    • So, (B) →\to→ (III)

    (C) Latent heat

    • Latent heat here means specific latent heat, defined as heat required per unit mass for change of phase: L=QmL = \frac{Q}{m}L=mQ​
    • Its SI unit is J kg−1\mathrm{J\,kg^{-1}}Jkg−1
    • So, (C) →\to→ (I)

    (D) Thermal conductivity

    • From Fourier's law, Qt=kAΔTL\frac{Q}{t} = kA\frac{\Delta T}{L}tQ​=kALΔT​
    • Therefore, k=Q/tA(ΔT/L)k = \frac{Q/t}{A(\Delta T/L)}k=A(ΔT/L)Q/t​
    • SI unit of thermal conductivity is W m−1 K−1=J m−1 K−1 s−1\mathrm{W\,m^{-1}\,K^{-1}} = \mathrm{J\,m^{-1}\,K^{-1}\,s^{-1}}Wm−1K−1=Jm−1K−1s−1
    • So, (D) →\to→ (IV)
  2. Final matching

    (A)−(II), (B)−(III), (C)−(I), (D)−(IV)\boxed{(A)-(II),\ (B)-(III),\ (C)-(I),\ (D)-(IV)}(A)−(II), (B)−(III), (C)−(I), (D)−(IV)​

  3. Compare with options

    This corresponds to Option D.

  4. Comparison with stored correct answer

    Stored correct answer = D

    Our derived answer = D

    Hence, the answer agrees with the stored correct answer.

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