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Electrochemistry question

2023 · 30 Jan · Shift 1 · Q18

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JEE Main
Chemistry
Electrochemistry
2023 · 30 Jan · Shift 1 · Q18

Electrochemistry question

2023 · 30 Jan · Shift 1 · Q18

JEE MainChemistryElectrochemistryNumerical+4 / −1

Consider the cell

\mathrm{Pt}_{(\mathrm{s})}\left|\mathrm{H}_{2}(\mathrm{~g}, 1 \mathrm{~atm})\right| \mathrm{H}^{+}(\mathrm{aq}, 1 \mathrm{M})|| \mathrm{Fe}^{3+}(\mathrm{aq}), \mathrm{Fe}^{2+}(\mathrm{aq}) \mid \operatorname{Pt}(\mathrm{s})

When the potential of the cell is

0.712 \mathrm{~V}

at

298 \mathrm{~K}

, the ratio

\left[\mathrm{Fe}^{2+}\right] /\left[\mathrm{Fe}^{3+}\right]

is

\underline{\hspace{2cm}}

. (Nearest integer) Given :

\mathrm{Fe}^{3+}+\mathrm{e}^{-}=\mathrm{Fe}^{2+}, \mathrm{E}^{\theta} \mathrm{Fe}^{3+}, \mathrm{Fe}^{2+} \mid \mathrm{Pt}=0.771 \frac{2.303 \mathrm{RT}}{\mathrm{F}}=0.06 \mathrm{~V}

Numerical answer

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