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Electrochemistry question

2023 · 30 Jan · Shift 2 · Q20

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JEE Main
Chemistry
Electrochemistry
2023 · 30 Jan · Shift 2 · Q20

Electrochemistry question

2023 · 30 Jan · Shift 2 · Q20

JEE MainChemistryElectrochemistryNumerical+4 / −1

The electrode potential of the following half cell at

298 \mathrm{~K}\mathrm{X}\left|\mathrm{X}^{2+}(0.001 \mathrm{M}) \| \mathrm{Y}^{2+}(0.01 \mathrm{M})\right| \mathrm{Y}

is

\underline{\hspace{2cm}}

\times 10^{-2} \mathrm{~V}

(Nearest integer) Given:

\mathrm{E}^{0} _ {\mathrm{X}^{2+} \mid \mathrm{X}}=-2.36 \mathrm{~V}\mathrm{E}_{\mathrm{Y}^{2+} \mid \mathrm{Y}}^{0}=+0.36 \mathrm{~V}\frac{2.303 \mathrm{RT}}{\mathrm{F}}=0.06 \mathrm{~V}

Numerical answer

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