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Electrochemistry question

2022 · 25 Jul · Shift 1 · Q14
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Electrochemistry question

2022 · 25 Jul · Shift 1 · Q14

JEE MainChemistryElectrochemistryNumerical+4 / −1
The cell potential for Zn∣Zn2+(aq)∣∣Snx+∣Sn\mathrm{Zn}\left|\mathrm{Zn}^{2+}(\mathrm{aq})\right|\left|\mathrm{Sn}^{x+}\right| \mathrm{Sn}Zn​Zn2+(aq)​​Snx+​Sn is 0.801 V0.801 \mathrm{~V}0.801 V at 298 K298 \mathrm{~K}298 K. The reaction quotient for the above reaction is 10−210^{-2}10−2. The number of electrons involved in the given electrochemical cell reaction is ‾\underline{\hspace{2cm}}​. (\left(\right.( Given :EZn2+∣Zno=−0.763 V,ESnx+∣Sno=+0.008 V: \mathrm{E}_{\mathrm{Zn}^{2+} \mid \mathrm{Zn}}^{\mathrm{o}}=-0.763 \mathrm{~V}, \mathrm{E}_{\mathrm{Sn}^{x+} \mid \mathrm{Sn}}^{\mathrm{o}}=+0.008 \mathrm{~V}:EZn2+∣Zno​=−0.763 V,ESnx+∣Sno​=+0.008 V and 2.303RTF=0.06 V)\left.\frac{2.303 \mathrm{RT}}{\mathrm{F}}=0.06 \mathrm{~V}\right)F2.303RT​=0.06 V)
Numerical answer
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