JEE MainChemistryCoordination CompoundsMCQ+4 / −1
Given below are two statements : Statement I : is square planar and diamagnetic complex, with dsp2 hybridization for Ni but is tetrahedral, paramagnetic and with sp3-hybridication for Ni. Statement II : and both have same d-electron configuration have same geometry and are paramagnetic. In light the above statements, choose the correct answer from the options given below :
- ABoth Statement I and Statement II are true.
- BBoth Statement I and Statement II are false.
- CStatement I is correct but Statement II is false.
- DStatement I is false but Statement II is correct.
View written solutionFree
Correct answer: B
-
Analyze Statement I
We examine both complexes mentioned.
(a)
- Oxidation state of Ni:
- So, has configuration:
- is a strong field ligand, so pairing occurs.
- For with strong field in coordination number 4, the complex becomes square planar with hybridization.
- All electrons are paired, so it is diamagnetic.
Hence this part is correct.
(b)
- CO is a neutral ligand, so oxidation state of Ni is .
- Configuration of :
- In , nickel uses hybridization and forms a tetrahedral complex.
- All electrons become paired in the metal-ligand bonding situation, so is diamagnetic, not paramagnetic.
Therefore, Statement I says " is tetrahedral, paramagnetic and with hybridization".
- Tetrahedral: true
- : true
- Paramagnetic: false
So Statement I is false.
-
Analyze Statement II
Statement II says: and both have same -electron configuration, same geometry and are paramagnetic.
(a)
- Oxidation state of Ni:
- So, is .
- is a weak field ligand, so no pairing occurs.
- Hence the complex is tetrahedral and paramagnetic.
(b)
- Ni oxidation state is .
- Thus it is not in the same sense as ; the metal is with valence configuration .
- Geometry is tetrahedral.
- But it is diamagnetic, not paramagnetic.
So in Statement II:
- same geometry: true
- same -electron configuration: commonly treated as not same oxidation-state electronic situation; in standard coordination chemistry comparison, has while has
- both paramagnetic: false
Therefore Statement II is false.
-
Final conclusion
- Statement I: False
- Statement II: False
Therefore, the correct option is:
-
Comparison with stored answer
Stored correct answer: B
My derived answer matches the stored answer.
More from Coordination Compounds
- Among the given complexes, number of paramagnetic complexes is .2022 · Numerical
- (a) , (b) , (c) and (d) . Number of complex(es) which will exist in cis-trans form is/are .2022 · Numerical
- should be an inner orbital complex. Ignoring the pairing energy, the value of crystal field stabilization energy for this complex is . (Nearest…2022 · Numerical
- Sum of oxidation state (magnitude) and coordination number of cobalt in is . Includes diagram2022 · Numerical
- Octahedral complexes of copper(II) undergo structural distortion (Jahn-Teller). Which one of the given copper (II) complexes will show the maximum structural distortion? (en - ethylenediamine; …2022 · MCQ
- Given below are two statements. Statement I : In . 5, Cu-O bonds are present. Statement II : In . 5, ligands coordinating with Cu(II) ion are O-and S-based ligands. In the light of the…2022 · MCQ
- In the following brown complex, the oxidation state of iron is +. 2022 · Numerical
- Spin only magnetic moment ( s) of is B.M. (Nearest integer)2022 · Numerical