- A
- B
- Ccis-
- Dtrans-
View written solutionFree
Correct answer: A
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Electronic configuration of in an octahedral field
Copper(II) is .
In an octahedral crystal field:
Since the set is unevenly occupied, octahedral complexes show Jahn–Teller distortion.
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Nature of Jahn–Teller distortion in systems
For octahedral complexes, distortion is usually tetragonal elongation or sometimes compression, in order to remove degeneracy.
The distortion becomes more pronounced when:
- the octahedral environment is more flexible,
- all six ligands are identical and can rearrange freely,
- there is no rigid chelate constraint.
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Examine each option
Option A:
- Complex cation is .
- It is a regular octahedral aqua complex with six identical monodentate ligands.
- Water is a relatively weak ligand and offers little structural rigidity.
- Therefore, Jahn–Teller distortion can occur most freely and strongly.
Option B:
- One bidentate ligand introduces chelation.
- Chelation makes the structure more rigid than the pure aqua complex.
- Hence distortion is present, but less than in option A.
Option C: cis-
- Two bidentate ligands strongly constrain the geometry.
- The cis arrangement further fixes ligand positions.
- Structural flexibility is less, so Jahn–Teller distortion is reduced compared with A.
Option D: trans-
- Again, two chelating ligands make the complex rigid.
- Though trans geometry may allow axial elongation along the axis, the chelate rings still reduce overall distortion compared with the fully aquated complex.
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Conclusion
The complex showing the maximum Jahn–Teller distortion will be the one with the least rigidity and most freely distortable octahedral environment:
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Comparison with stored correct answer
Stored correct answer:
Derived answer:
Hence, the derived answer agrees with the stored answer.
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