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Coordination Compounds question

2022 · 29 Jul · Shift 2 · Q8
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Coordination Compounds question

2022 · 29 Jul · Shift 2 · Q8

JEE MainChemistryCoordination CompoundsMCQ+4 / −1
Octahedral complexes of copper(II) undergo structural distortion (Jahn-Teller). Which one of the given copper (II) complexes will show the maximum structural distortion? (en - ethylenediamine; H2 N−CH2−CH2−NH2\mathrm{H}_{2} \mathrm{~N}_{-} \mathrm{CH}_{2}-\mathrm{CH}_{2}-\mathrm{NH}_{2}H2​ N−​CH2​−CH2​−NH2​)
  1. A
    [Cu(H2O)6]SO4\left[\mathrm{Cu}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right] \mathrm{SO}_{4}[Cu(H2​O)6​]SO4​
  2. B
    [Cu(en)(H2O)4]SO4\left[\mathrm{Cu}(\mathrm{en})\left(\mathrm{H}_{2} \mathrm{O}\right)_{4}\right] \mathrm{SO}_{4}[Cu(en)(H2​O)4​]SO4​
  3. C
    cis-[Cu(en)2Cl2]\left[\mathrm{Cu}\left(\mathrm{en})_{2} \mathrm{Cl}_{2}\right]\right.[Cu(en)2​Cl2​]
  4. D
    trans-[Cu(en)2Cl2]\left[\mathrm{Cu}\left(\mathrm{en})_{2} \mathrm{Cl}_{2}\right]\right.[Cu(en)2​Cl2​]
View written solutionFree

Correct answer: A

  1. Electronic configuration of Cu2+\mathrm{Cu^{2+}}Cu2+ in an octahedral field

    Copper(II) is 3d93d^93d9.

    In an octahedral crystal field: t2g6eg3t_{2g}^6 e_g^3t2g6​eg3​

    Since the ege_geg​ set is unevenly occupied, octahedral Cu2+\mathrm{Cu^{2+}}Cu2+ complexes show Jahn–Teller distortion.

  2. Nature of Jahn–Teller distortion in d9d^9d9 systems

    For d9d^9d9 octahedral complexes, distortion is usually tetragonal elongation or sometimes compression, in order to remove degeneracy.

    The distortion becomes more pronounced when:

    • the octahedral environment is more flexible,
    • all six ligands are identical and can rearrange freely,
    • there is no rigid chelate constraint.
  3. Examine each option

    Option A: [Cu(H2O)6]SO4\left[\mathrm{Cu(H_2O)_6}\right]\mathrm{SO_4}[Cu(H2​O)6​]SO4​

    • Complex cation is [Cu(H2O)6]2+\left[\mathrm{Cu(H_2O)_6}\right]^{2+}[Cu(H2​O)6​]2+.
    • It is a regular octahedral aqua complex with six identical monodentate ligands.
    • Water is a relatively weak ligand and offers little structural rigidity.
    • Therefore, Jahn–Teller distortion can occur most freely and strongly.

    Option B: [Cu(en)(H2O)4]SO4\left[\mathrm{Cu(en)(H_2O)_4}\right]\mathrm{SO_4}[Cu(en)(H2​O)4​]SO4​

    • One bidentate ligand en\mathrm{en}en introduces chelation.
    • Chelation makes the structure more rigid than the pure aqua complex.
    • Hence distortion is present, but less than in option A.

    Option C: cis-[Cu(en)2Cl2]\left[\mathrm{Cu(en)_2Cl_2}\right][Cu(en)2​Cl2​]

    • Two bidentate en\mathrm{en}en ligands strongly constrain the geometry.
    • The cis arrangement further fixes ligand positions.
    • Structural flexibility is less, so Jahn–Teller distortion is reduced compared with A.

    Option D: trans-[Cu(en)2Cl2]\left[\mathrm{Cu(en)_2Cl_2}\right][Cu(en)2​Cl2​]

    • Again, two chelating en\mathrm{en}en ligands make the complex rigid.
    • Though trans geometry may allow axial elongation along the Cl\mathrm{Cl}Cl axis, the chelate rings still reduce overall distortion compared with the fully aquated complex.
  4. Conclusion

    The complex showing the maximum Jahn–Teller distortion will be the one with the least rigidity and most freely distortable octahedral environment: [Cu(H2O)6]SO4\boxed{\left[\mathrm{Cu(H_2O)_6}\right]\mathrm{SO_4}}[Cu(H2​O)6​]SO4​​

  5. Comparison with stored correct answer

    Stored correct answer: AAA

    Derived answer: AAA

    Hence, the derived answer agrees with the stored answer.

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