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Coordination Compounds question

2021 · 17 Mar · Shift 2 · Q10
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  5. /2021 · 17 Mar · Shift 2 · Q10

Coordination Compounds question

2021 · 17 Mar · Shift 2 · Q10

JEE MainChemistryCoordination CompoundsMCQ+4 / −1
Match List - I with List - II :

List - I
 List - II
(a) [Co(NH3)6][Cr(CN)6][Co{(N{H_3})_6}][Cr{(CN)_6}][Co(NH3​)6​][Cr(CN)6​] (i) Linkage isomerism
(b) [Co(NH3)3(NO2)3][Co{(N{H_3})_3}{(N{O_2})_3}][Co(NH3​)3​(NO2​)3​] (ii) Solvate isomerism
(c) [Cr(H2O)6Cl3[Cr{({H_2}O)_6}C{l_3}[Cr(H2​O)6​Cl3​ (iii) Co-ordination isomerism
(d) cis−[CrCl2(ox)2]3−cis - {[CrC{l_2}{(ox)_2}]^{3 - }}cis−[CrCl2​(ox)2​]3− (iv) Optical isomerism


Choose the correct answer from the options given below :
  1. A
    (a)-(i), (b)-(ii), (c)-(iii), (d)-(iv)
  2. B
    (a)-(iii), (b)-(i), (c)-(ii), (d)-(iv)
  3. C
    (a)-(ii), (b)-(i), (c)-(iii), (d)-(iv)
  4. D
    (a)-(iv), (b)-(ii), (c)-(iii), (d)-(i)
View written solutionFree

Correct answer: B

  1. Identify the type of isomerism for each complex

(a) [Co(NH3)6][Cr(CN)6][Co(NH_3)_6][Cr(CN)_6][Co(NH3​)6​][Cr(CN)6​]

This is a salt containing a complex cation and a complex anion.

Such compounds can show coordination isomerism by interchange of ligands between cationic and anionic coordination spheres, e.g. [Co(NH3)6][Cr(CN)6]↔[Cr(NH3)6][Co(CN)6][Co(NH_3)_6][Cr(CN)_6] \leftrightarrow [Cr(NH_3)_6][Co(CN)_6][Co(NH3​)6​][Cr(CN)6​]↔[Cr(NH3​)6​][Co(CN)6​]

So, (a)→(iii)Coordination isomerism(a) \to (iii)\quad \text{Coordination isomerism}(a)→(iii)Coordination isomerism

(b) [Co(NH3)3(NO2)3][Co(NH_3)_3(NO_2)_3][Co(NH3​)3​(NO2​)3​]

Here NO2−NO_2^-NO2−​ is an ambidentate ligand. It can coordinate through:

  • N atom: nitro
  • O atom: nitrito

Hence this complex shows linkage isomerism.

So, (b)→(i)Linkage isomerism(b) \to (i)\quad \text{Linkage isomerism}(b)→(i)Linkage isomerism

(c) [Cr(H2O)6]Cl3[Cr(H_2O)_6]Cl_3[Cr(H2​O)6​]Cl3​

This can form compounds like: [Cr(H2O)6]Cl3,[Cr(H2O)5Cl]Cl2⋅H2O,[Cr(H2O)4Cl2]Cl⋅2H2O[Cr(H_2O)_6]Cl_3, \quad [Cr(H_2O)_5Cl]Cl_2\cdot H_2O, \quad [Cr(H_2O)_4Cl_2]Cl\cdot 2H_2O[Cr(H2​O)6​]Cl3​,[Cr(H2​O)5​Cl]Cl2​⋅H2​O,[Cr(H2​O)4​Cl2​]Cl⋅2H2​O These differ in whether water is inside or outside the coordination sphere.

This is solvate isomerism (specifically hydrate isomerism).

So, (c)→(ii)Solvate isomerism(c) \to (ii)\quad \text{Solvate isomerism}(c)→(ii)Solvate isomerism

(d) cis−[CrCl2(ox)2]3−cis-[CrCl_2(ox)_2]^{3-}cis−[CrCl2​(ox)2​]3−

Here oxoxox = oxalate, a bidentate ligand. In the cis form with two bidentate ligands, the complex can exist as non-superimposable mirror images.

Therefore it shows optical isomerism.

So, (d)→(iv)Optical isomerism(d) \to (iv)\quad \text{Optical isomerism}(d)→(iv)Optical isomerism

  1. Final matching

Thus the correct matching is:

(a)−(iii),(b)−(i),(c)−(ii),(d)−(iv)(a)-(iii),\quad (b)-(i),\quad (c)-(ii),\quad (d)-(iv)(a)−(iii),(b)−(i),(c)−(ii),(d)−(iv)

  1. Compare with options This corresponds to Option B.

  2. Comparison with stored answer Stored correct answer = B

Our derived answer = B

Hence, they agree.

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