Consider, PF_5, BrF_5, PCl_3, SF_6,[ICl_4]^-, ClF_3 and IF_5 . Amongst the above molecule(s)/ion(s), the number of molecule(s)/ion(s) having sp^3~d^2 hybridisation is \underline\hspace2cm .

Chemical Bonding and Molecular Structure PYQ — JEE Main 2022 · 29 Jul · Shift 2 · Q16 with Solution

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Correct answer: 4

Find the steric number of the central atom for each species.

For a central atom, if the total number of electron pairs around it is:

$4 \Rightarrow sp^3$
$5 \Rightarrow sp^3d$
$6 \Rightarrow sp^3d^2$

So we must count bond pairs + lone pairs on the central atom.

Check each molecule/ion one by one

(i) $\mathrm{PF_5}$

Central atom: P
Bonds: 5
Lone pairs on P: 0
Total electron pairs $=5$

Hence, hybridisation $= sp^3d$ .

Not $sp^3d^2$ .

(ii) $\mathrm{BrF_5}$

Central atom: Br
Br has 7 valence electrons.
It forms 5 bonds with F, leaving 1 lone pair.
Total electron pairs $=5+1=6$

Hence, hybridisation $= sp^3d^2$ .

Count this.

(iii) $\mathrm{PCl_3}$

Central atom: P
P has 5 valence electrons.
It forms 3 bonds with Cl, leaving 1 lone pair.
Total electron pairs $=3+1=4$

Hence, hybridisation $= sp^3$ .

Not $sp^3d^2$ .

(iv) $\mathrm{SF_6}$

Central atom: S
Bonds: 6
Lone pairs: 0
Total electron pairs $=6$

Hence, hybridisation $= sp^3d^2$ .

Count this.

(v) $[\mathrm{ICl_4}]^-$

Central atom: I
I has 7 valence electrons, and one extra electron due to negative charge $\Rightarrow 8$ electrons.
It forms 4 bonds with Cl, leaving 2 lone pairs.
Total electron pairs $=4+2=6$

Hence, hybridisation $= sp^3d^2$ .

Count this.

(vi) $\mathrm{ClF_3}$

Central atom: Cl
Cl has 7 valence electrons.
It forms 3 bonds with F, leaving 2 lone pairs.
Total electron pairs $=3+2=5$

Hence, hybridisation $= sp^3d$ .

Not $sp^3d^2$ .

(vii) $\mathrm{IF_5}$

Central atom: I
I has 7 valence electrons.
It forms 5 bonds with F, leaving 1 lone pair.
Total electron pairs $=5+1=6$

Hence, hybridisation $= sp^3d^2$ .

Count this.

Total number with $sp^3d^2$ hybridisation

The species are:

$\mathrm{BrF_5}$
$\mathrm{SF_6}$
$[\mathrm{ICl_4}]^-$
$\mathrm{IF_5}$

So the required number is $4$

Comparison with stored correct answer

Stored correct answer = $4$

Our derived answer = $4$

So they agree.

Chemical Bonding and Molecular Structure question

Chemical Bonding and Molecular Structure question

(i) $\mathrm{PF_5}$

(ii) $\mathrm{BrF_5}$

(iii) $\mathrm{PCl_3}$

(iv) $\mathrm{SF_6}$

(v) $[\mathrm{ICl_4}]^-$

(vi) $\mathrm{ClF_3}$

(vii) $\mathrm{IF_5}$

More from Chemical Bonding and Molecular Structure

Chemical Bonding and Molecular Structure question

Chemical Bonding and Molecular Structure question

(i) $\mathrm{PF_5}$

(ii) $\mathrm{BrF_5}$

(iii) $\mathrm{PCl_3}$

(iv) $\mathrm{SF_6}$

(v) $[\mathrm{ICl_4}]^-$

(vi) $\mathrm{ClF_3}$

(vii) $\mathrm{IF_5}$

More from Chemical Bonding and Molecular Structure

(i) PF5\mathrm{PF_5}PF5​

(ii) BrF5\mathrm{BrF_5}BrF5​

(iii) PCl3\mathrm{PCl_3}PCl3​

(iv) SF6\mathrm{SF_6}SF6​

(v) [ICl4]−[\mathrm{ICl_4}]^-[ICl4​]−

(vi) ClF3\mathrm{ClF_3}ClF3​

(vii) IF5\mathrm{IF_5}IF5​

More from Chemical Bonding and Molecular Structure

(i) PF5\mathrm{PF_5}PF5​

(ii) BrF5\mathrm{BrF_5}BrF5​

(iii) PCl3\mathrm{PCl_3}PCl3​

(iv) SF6\mathrm{SF_6}SF6​

(v) [ICl4]−[\mathrm{ICl_4}]^-[ICl4​]−

(vi) ClF3\mathrm{ClF_3}ClF3​

(vii) IF5\mathrm{IF_5}IF5​

More from Chemical Bonding and Molecular Structure

(i) $\mathrm{PF_5}$

(ii) $\mathrm{BrF_5}$

(iii) $\mathrm{PCl_3}$

(iv) $\mathrm{SF_6}$

(v) $[\mathrm{ICl_4}]^-$

(vi) $\mathrm{ClF_3}$

(vii) $\mathrm{IF_5}$

(i) $\mathrm{PF_5}$

(ii) $\mathrm{BrF_5}$

(iii) $\mathrm{PCl_3}$

(iv) $\mathrm{SF_6}$

(v) $[\mathrm{ICl_4}]^-$

(vi) $\mathrm{ClF_3}$

(vii) $\mathrm{IF_5}$