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Limits Continuity and Differentiability question

2023 · 10 Apr · Shift 1 · Q39
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  5. /2023 · 10 Apr · Shift 1 · Q39

Limits Continuity and Differentiability question

2023 · 10 Apr · Shift 1 · Q39

JEE MainMathematicsLimits Continuity and DifferentiabilityNumerical+4 / −1
Let f:(−2,2)→Rf:( - 2,2) \to Rf:(−2,2)→R be defined by f(x)={x[x],−2<x<0(x−1)[x],0≤x≤2f(x) = \left\{ {\begin{matrix} {x[x],} & { - 2 \lt x \lt 0} \\ {(x - 1)[x],} & {0 \le x \le 2} \\ \end{matrix} } \right.f(x)={x[x],(x−1)[x],​−2<x<00≤x≤2​ where [x][x][x] denotes the greatest integer function. If m and n respectively are the number of points in (−2,2)( - 2,2)(−2,2) at which y=∣f(x)∣y = |f(x)|y=∣f(x)∣ is not continuous and not differentiable, then m+nm + nm+n is equal to ‾\underline{\hspace{2cm}}​.
Numerical answer
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