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Limits Continuity and Differentiability question

2023 · 8 Apr · Shift 2 · Q39
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  5. /2023 · 8 Apr · Shift 2 · Q39

Limits Continuity and Differentiability question

2023 · 8 Apr · Shift 2 · Q39

JEE MainMathematicsLimits Continuity and DifferentiabilityNumerical+4 / −1
Let k\mathrm{k}k and m\mathrm{m}m be positive real numbers such that the function f(x)={3x2+kx+1,0<x<1mx2+k2,x≥1f(x)=\left\{\begin{array}{cc}3 x^{2}+k \sqrt{x+1}, & 0 \lt x \lt 1 \\ m x^{2}+k^{2}, & x \geq 1\end{array}\right.f(x)={3x2+kx+1​,mx2+k2,​0<x<1x≥1​ is differentiable for all x>0x \gt 0x>0. Then 8f′(8)f′(18)\frac{8 f^{\prime}(8)}{f^{\prime}\left(\frac{1}{8}\right)}f′(81​)8f′(8)​ is equal to ‾\underline{\hspace{2cm}}​.
Numerical answer
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