Doubts
Sign in
12thPass logo
New chatPYQ LibraryDoubtsRank report
Sign in to see Recents
Sign in to save progress →
Doubts
Sign in

Limits Continuity and Differentiability question

2023 · 24 Jan · Shift 1 · Q27
Guest · try one question or challengeGuest · try one question or challenge
  1. PYQ Library
  2. /JEE Main
  3. /Mathematics
  4. /Limits Continuity and Differentiability
  5. /2023 · 24 Jan · Shift 1 · Q27

Limits Continuity and Differentiability question

2023 · 24 Jan · Shift 1 · Q27

JEE MainMathematicsLimits Continuity and DifferentiabilityMCQ+4 / −1
lim⁡t→0(11sin⁡2t+21sin⁡2t + ... + n1sin⁡2t)sin⁡2t\mathop {\lim }\limits_{t \to 0} {\left( {{1^{{1 \over {{{\sin }^2}t}}}} + {2^{{1 \over {{{\sin }^2}t}}}}\, + \,...\, + \,{n^{{1 \over {{{\sin }^2}t}}}}} \right)^{{{\sin }^2}t}}t→0lim​(1sin2t1​+2sin2t1​+...+nsin2t1​)sin2t is equal to
  1. A
    n(n+1)2{{n(n + 1)} \over 2}2n(n+1)​
  2. B
    n
  3. C
    n 2^22 + n
  4. D
    n 2^22
PreviousNext

More from Limits Continuity and Differentiability

  • Let f(x)={x2sin(x1​)0​,xe0,x=0​ Then at x=02023 · MCQ
  • The set of all values of a for which x→alim​([x−5]−[2x+2])=0, where [α] denotes the greatest integer less than or equal to α is equal to2023 · MCQ
  • The value of n→∞lim​2n4+4n+3​−n4+5n+4​1+2−3+4+5−6+.....+(3n−2)+(3n−1)−3n​ is :2023 · MCQ
  • If the function f(x)=⎩⎨⎧​(1+∣cosx∣)∣cosx∣λ​μecot4xcot6x​​,,,​0<x<2π​x=2π​2π​<x<π​…2023 · MCQ
  • Let x=2 be a root of the equation x2+px+q=0 and f(x)={(x−2p)41−cos(x2−4px+q2+8q+16)​,0,​xe2px=2p​ Then x→2p+lim​[f(x)]…2023 · MCQ
  • Suppose f:R→(0,∞) be a differentiable function such that 5f(x+y)=f(x)⋅f(y),∀x,y∈R. If f(3)=320, then ∑n=05​f(n) is equal to :2023 · MCQ
  • Let f,g and h be the real valued functions defined on R as f(x)={∣x∣x​,1,​xeq0x=0​g(x)={(x+1)sin(x+1)​,1,​xeq−1x=−1​…2023 · MCQ
  • x→∞lim​(x+x2−1​)6+(x−x2−1​)6(3x+1​+3x−1​)6+(3x+1​−3x−1​)6​x32023 · MCQ