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Limits Continuity and Differentiability question

2023 · 8 Apr · Shift 2 · Q32
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  5. /2023 · 8 Apr · Shift 2 · Q32

Limits Continuity and Differentiability question

2023 · 8 Apr · Shift 2 · Q32

JEE MainMathematicsLimits Continuity and DifferentiabilityMCQ+4 / −1
If α>β>0\alpha \gt \beta \gt 0α>β>0 are the roots of the equation ax2+bx+1=0a x^{2}+b x+1=0ax2+bx+1=0, and lim⁡x→1α(1−cos⁡(x2+bx+a)2(1−αx)2)12=1k(1β−1α), then k is equal to \lim_{x \rightarrow \frac{1}{\alpha}}\left(\frac{1-\cos \left(x^{2}+b x+a\right)}{2(1-\alpha x)^{2}}\right)^{\frac{1}{2}}=\frac{1}{k}\left(\frac{1}{\beta}-\frac{1}{\alpha}\right), \text { then } \mathrm{k} \text { is equal to }x→α1​lim​(2(1−αx)21−cos(x2+bx+a)​)21​=k1​(β1​−α1​), then k is equal to  :
  1. A
    2β2 \beta2β
  2. B
    β\betaβ
  3. C
    α\alphaα
  4. D
    2α2 \alpha2α
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