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Limits Continuity and Differentiability question

2022 · 25 Jul · Shift 1 · Q25
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  5. /2022 · 25 Jul · Shift 1 · Q25

Limits Continuity and Differentiability question

2022 · 25 Jul · Shift 1 · Q25

JEE MainMathematicsLimits Continuity and DifferentiabilityMCQ+4 / −1
If lim⁡n→∞(n2−n−1+nα+β)=0\mathop {\lim }\limits_{n \to \infty } \left( {\sqrt {{n^2} - n - 1} + n\alpha + \beta } \right) = 0n→∞lim​(n2−n−1​+nα+β)=0, then 8(α+β)8(\alpha+\beta)8(α+β) is equal to :
  1. A
    4
  2. B
    −-− 8
  3. C
    −-− 4
  4. D
    8
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