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Limits Continuity and Differentiability question

2022 · 25 Jul · Shift 2 · Q27
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  5. /2022 · 25 Jul · Shift 2 · Q27

Limits Continuity and Differentiability question

2022 · 25 Jul · Shift 2 · Q27

JEE MainMathematicsLimits Continuity and DifferentiabilityMCQ+4 / −1
lim⁡x→π482−(cos⁡x+sin⁡x)72−2sin⁡2x\lim\limits_{x \rightarrow \frac{\pi}{4}} \frac{8 \sqrt{2}-(\cos x+\sin x)^{7}}{\sqrt{2}-\sqrt{2} \sin 2 x}x→4π​lim​2​−2​sin2x82​−(cosx+sinx)7​ is equal to
  1. A
    14
  2. B
    7
  3. C
    14 2\sqrt22​
  4. D
    7 2\sqrt22​
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