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Limits Continuity and Differentiability question

2022 · 26 Jul · Shift 1 · Q30
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  5. /2022 · 26 Jul · Shift 1 · Q30

Limits Continuity and Differentiability question

2022 · 26 Jul · Shift 1 · Q30

JEE MainMathematicsLimits Continuity and DifferentiabilityMCQ+4 / −1
If the function f(x)={log⁡e(1−x+x2)+log⁡e(1+x+x2)sec⁡x−cos⁡x,x∈(−π2,π2)−{0}k,x=0f(x) = \left\{ {\begin{matrix} {{{{{\log }_e}(1 - x + {x^2}) + {{\log }_e}(1 + x + {x^2})} \over {\sec x - \cos x}}} & , & {x \in \left( {{{ - \pi } \over 2},{\pi \over 2}} \right) - \{ 0\} } \\ k & , & {x = 0} \\ \end{matrix} } \right.f(x)={secx−cosxloge​(1−x+x2)+loge​(1+x+x2)​k​,,​x∈(2−π​,2π​)−{0}x=0​ is continuous at x = 0, then k is equal to:
  1. A
    1
  2. B
    −-− 1
  3. C
    e
  4. D
    0
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