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Limits Continuity and Differentiability question

2022 · 25 Jun · Shift 2 · Q27

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JEE Main
Mathematics
Limits Continuity and Differentiability
2022 · 25 Jun · Shift 2 · Q27

Limits Continuity and Differentiability question

2022 · 25 Jun · Shift 2 · Q27

JEE MainMathematicsLimits Continuity and DifferentiabilityMCQ+4 / −1

\mathop {\lim }\limits_{x \to {\pi \over 2}} \left( {{{\tan }^2}x\left( {{{(2{{\sin }^2}x + 3\sin x + 4)}^{{1 \over 2}}} - {{({{\sin }^2}x + 6\sin x + 2)}^{{1 \over 2}}}} \right)} \right)

is equal to

A
${1 \over {12}}$
B
$-{1 \over {18}}$
C
$-{1 \over {12}}$
D
${1 \over {6}}$

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