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Differential Equations question

2022 · 29 Jun · Shift 1 · Q21
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  5. /2022 · 29 Jun · Shift 1 · Q21

Differential Equations question

2022 · 29 Jun · Shift 1 · Q21

JEE MainMathematicsDifferential EquationsMCQ+4 / −1
Let the solution curve of the differential equation xdydx−y=y2+16x2x{{dy} \over {dx}} - y = \sqrt {{y^2} + 16{x^2}}xdxdy​−y=y2+16x2​, y(1)=3y(1) = 3y(1)=3 be y=y(x)y = y(x)y=y(x). Then y(2) is equal to:
  1. A
    15
  2. B
    11
  3. C
    13
  4. D
    17
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