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Differential Equations question

2022 · 29 Jun · Shift 1 · Q37

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JEE Main
Mathematics
Differential Equations
2022 · 29 Jun · Shift 1 · Q37

Differential Equations question

2022 · 29 Jun · Shift 1 · Q37

JEE MainMathematicsDifferential EquationsNumerical+4 / −1

Let y = y(x) be the solution of the differential equation $${{dy} \over {dx}} + {{\sqrt 2 y} \over {2{{\cos }^4}x - {{\cos }^2}x}} = x{e^{{{\tan }^{ - 1}}(\sqrt 2 \cot 2x)}},\,0 2 is equal to $\underline{\hspace{2cm}}$.

Numerical answer

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