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Differential Equations question

2022 · 29 Jul · Shift 2 · Q30
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  5. /2022 · 29 Jul · Shift 2 · Q30

Differential Equations question

2022 · 29 Jul · Shift 2 · Q30

JEE MainMathematicsDifferential EquationsMCQ+4 / −1
Let y=y(x)y=y(x)y=y(x) be the solution curve of the differential equation dydx+(2x2+11x+13x3+6x2+11x+6)y=(x+3)x+1,x>−1\frac{d y}{d x}+\left(\frac{2 x^{2}+11 x+13}{x^{3}+6 x^{2}+11 x+6}\right) y=\frac{(x+3)}{x+1}, x\gt -1dxdy​+(x3+6x2+11x+62x2+11x+13​)y=x+1(x+3)​,x>−1, which passes through the point (0,1)(0,1)(0,1). Then y(1)y(1)y(1) is equal to :
  1. A
    12\frac{1}{2}21​
  2. B
    32\frac{3}{2}23​
  3. C
    52\frac{5}{2}25​
  4. D
    72\frac{7}{2}27​
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