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Differential Equations question

2021 · 1 Sep · Shift 2 · Q28

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JEE Main
Mathematics
Differential Equations
2021 · 1 Sep · Shift 2 · Q28

Differential Equations question

2021 · 1 Sep · Shift 2 · Q28

JEE MainMathematicsDifferential EquationsMCQ+4 / −1

If y = y(x) is the solution curve of the differential equation

{x^2}dy + \left( {y - {1 \over x}} \right)dx = 0

; x > 0 and y(1) = 1, then

y\left( {{1 \over 2}} \right)

is equal to :

A
${3 \over 2} - {1 \over {\sqrt e }}$
B
$3 + {1 \over {\sqrt e }}$
C
3 + e
D
3 $-$ e

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