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Differential Equations question

2022 · 29 Jun · Shift 2 · Q36
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  5. /2022 · 29 Jun · Shift 2 · Q36

Differential Equations question

2022 · 29 Jun · Shift 2 · Q36

JEE MainMathematicsDifferential EquationsNumerical+4 / −1
Let y = y(x), x > 1, be the solution of the differential equation (x−1)dydx+2xy=1x−1(x - 1){{dy} \over {dx}} + 2xy = {1 \over {x - 1}}(x−1)dxdy​+2xy=x−11​, with y(2)=1+e42e4y(2) = {{1 + {e^4}} \over {2{e^4}}}y(2)=2e41+e4​. If y(3)=eα+1βeαy(3) = {{{e^\alpha } + 1} \over {\beta {e^\alpha }}}y(3)=βeαeα+1​, then the value of α+β\alpha + \betaα+β is equal to ‾\underline{\hspace{2cm}}​.
Numerical answer
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