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Differential Equations question

2021 · 16 Mar · Shift 2 · Q31
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  2. /JEE Main
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  4. /Differential Equations
  5. /2021 · 16 Mar · Shift 2 · Q31

Differential Equations question

2021 · 16 Mar · Shift 2 · Q31

JEE MainMathematicsDifferential EquationsMCQ+4 / −1
Let C1 be the curve obtained by the solution of differential equation 2xydydx=y2−x2,x>02xy{{dy} \over {dx}} = {y^2} - {x^2},x \gt 02xydxdy​=y2−x2,x>0. Let the curve C2 be the solution of 2xyx2−y2=dydx{{2xy} \over {{x^2} - {y^2}}} = {{dy} \over {dx}}x2−y22xy​=dxdy​. If both the curves pass through (1, 1), then the area enclosed by the curves C1 and C2 is equal to :
  1. A
    π4{\pi \over 4}4π​ + 1
  2. B
    π\piπ + 1
  3. C
    π−\pi-π− 1
  4. D
    π2−{\pi \over 2}-2π​− 1
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