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Differential Equations question

2021 · 16 Mar · Shift 1 · Q36
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  2. /JEE Main
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  4. /Differential Equations
  5. /2021 · 16 Mar · Shift 1 · Q36

Differential Equations question

2021 · 16 Mar · Shift 1 · Q36

JEE MainMathematicsDifferential EquationsMCQ+4 / −1
If y = y(x) is the solution of the differential equation, dydx+2ytan⁡x=sin⁡x,y(π3)=0{{dy} \over {dx}} + 2y\tan x = \sin x,y\left( {{\pi \over 3}} \right) = 0dxdy​+2ytanx=sinx,y(3π​)=0, then the maximum value of the function y(x) over R is equal to:
  1. A
    18{1 \over 8}81​
  2. B
    8
  3. C
    −154-{15 \over 4}−415​
  4. D
    12{1 \over 2}21​
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