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Differential Equations question

2021 · 25 Jul · Shift 1 · Q30
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  4. /Differential Equations
  5. /2021 · 25 Jul · Shift 1 · Q30

Differential Equations question

2021 · 25 Jul · Shift 1 · Q30

JEE MainMathematicsDifferential EquationsMCQ+4 / −1
Let y = y(x) be the solution of the differential equation dydx=1+xey−x,−2<x<2,y(0)=0{{dy} \over {dx}} = 1 + x{e^{y - x}}, - \sqrt 2 \lt x \lt \sqrt 2 ,y(0) = 0dxdy​=1+xey−x,−2​<x<2​,y(0)=0 then, the minimum value of y(x),x∈(−2,2)y(x),x \in \left( { - \sqrt 2 ,\sqrt 2 } \right)y(x),x∈(−2​,2​) is equal to :
  1. A
    (2−3)−log⁡e2\left( {2 - \sqrt 3 } \right) - {\log _e}2(2−3​)−loge​2
  2. B
    (2+3)+log⁡e2\left( {2 + \sqrt 3 } \right) + {\log _e}2(2+3​)+loge​2
  3. C
    (1+3)−log⁡e(3−1)\left( {1 + \sqrt 3 } \right) - {\log _e}\left( {\sqrt 3 - 1} \right)(1+3​)−loge​(3​−1)
  4. D
    (1−3)−log⁡e(3−1)\left( {1 - \sqrt 3 } \right) - {\log _e}\left( {\sqrt 3 - 1} \right)(1−3​)−loge​(3​−1)
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