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Differential Equations question

2021 · 27 Aug · Shift 1 · Q27

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JEE Main
Mathematics
Differential Equations
2021 · 27 Aug · Shift 1 · Q27

Differential Equations question

2021 · 27 Aug · Shift 1 · Q27

JEE MainMathematicsDifferential EquationsMCQ+4 / −1

Let y = y(x) be the solution of the differential equation

{{dy} \over {dx}} = 2(y + 2\sin x - 5)x - 2\cos x

such that y(0) = 7. Then y(

\pi

) is equal to :

A
$2{e^{{\pi ^2}}} + 5$
B
${e^{{\pi ^2}}} + 5$
C
$3{e^{{\pi ^2}}} + 5$
D
$7{e^{{\pi ^2}}} + 5$

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