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Differential Equations question

2021 · 25 Jul · Shift 2 · Q40

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JEE Main
Mathematics
Differential Equations
2021 · 25 Jul · Shift 2 · Q40

Differential Equations question

2021 · 25 Jul · Shift 2 · Q40

JEE MainMathematicsDifferential EquationsMCQ+4 / −1

Let y = y(x) be the solution of the differential equation xdy = (y + x3 cosx)dx with y(

\pi

) = 0, then

y\left( {{\pi \over 2}} \right)

is equal to :

A
${{{\pi ^2}} \over 4} + {\pi \over 2}$
B
${{{\pi ^2}} \over 2} + {\pi \over 4}$
C
${{{\pi ^2}} \over 2} - {\pi \over 4}$
D
${{{\pi ^4}} \over 4} - {\pi \over 2}$

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