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Differential Equations question

2021 · 26 Feb · Shift 1 · Q42
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  5. /2021 · 26 Feb · Shift 1 · Q42

Differential Equations question

2021 · 26 Feb · Shift 1 · Q42

JEE MainMathematicsDifferential EquationsNumerical+4 / −1
If y = y(x) is the solution of the equation esin⁡ycos⁡ydydx+esin⁡ycos⁡x=cos⁡x{e^{\sin y}}\cos y{{dy} \over {dx}} + {e^{\sin y}}\cos x = \cos xesinycosydxdy​+esinycosx=cosx, y(0) = 0; then 1+y(π6)+32y(π3)+12y(π4)1 + y\left( {{\pi \over 6}} \right) + {{\sqrt 3 } \over 2}y\left( {{\pi \over 3}} \right) + {1 \over {\sqrt 2 }}y\left( {{\pi \over 4}} \right)1+y(6π​)+23​​y(3π​)+2​1​y(4π​) is equal to ‾\underline{\hspace{2cm}}​.
Numerical answer
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