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Differential Equations question

2021 · 26 Aug · Shift 2 · Q27

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JEE Main
Mathematics
Differential Equations
2021 · 26 Aug · Shift 2 · Q27

Differential Equations question

2021 · 26 Aug · Shift 2 · Q27

JEE MainMathematicsDifferential EquationsMCQ+4 / −1

Let y(x) be the solution of the differential equation 2x2 dy + (ey

-

2x)dx = 0, x > 0. If y(e) = 1, then y(1) is equal to :

A
0
B
2
C
loge 2
D
loge (2e)

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