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Differential Equations question

2021 · 25 Jul · Shift 1 · Q38
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  5. /2021 · 25 Jul · Shift 1 · Q38

Differential Equations question

2021 · 25 Jul · Shift 1 · Q38

JEE MainMathematicsDifferential EquationsNumerical+4 / −1
Let y = y(x) be solution of the following differential equation eydydx−2eysin⁡x+sin⁡xcos⁡2x=0,y(π2)=0{e^y}{{dy} \over {dx}} - 2{e^y}\sin x + \sin x{\cos ^2}x = 0,y\left( {{\pi \over 2}} \right) = 0eydxdy​−2eysinx+sinxcos2x=0,y(2π​)=0 If y(0)=log⁡e(α+βe−2)y(0) = {\log _e}(\alpha + \beta {e^{ - 2}})y(0)=loge​(α+βe−2), then 4(α+β)4(\alpha + \beta )4(α+β) is equal to ‾\underline{\hspace{2cm}}​.
Numerical answer
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