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Redox Reactions question

2024 · 31 Jan · Shift 2 · Q24
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Redox Reactions question

2024 · 31 Jan · Shift 2 · Q24

JEE MainChemistryRedox ReactionsNumerical+4 / −1
In the reaction of potassium dichromate, potassium chloride and sulfuric acid (conc.), the oxidation state of the chromium in the product is (+)‾(+)\underline{\hspace{2cm}}(+)​.
Numerical answer
View written solutionFree

Correct answer: 6

  1. Identify the reaction

Potassium dichromate reacts with potassium chloride and concentrated sulfuric acid to form chromyl chloride:

K2Cr2O7+4KCl+6H2SO4→2CrO2Cl2+6KHSO4+3H2OK_2Cr_2O_7 + 4KCl + 6H_2SO_4 \rightarrow 2CrO_2Cl_2 + 6KHSO_4 + 3H_2OK2​Cr2​O7​+4KCl+6H2​SO4​→2CrO2​Cl2​+6KHSO4​+3H2​O

So, the chromium-containing product is chromyl chloride, CrO2Cl2CrO_2Cl_2CrO2​Cl2​.

  1. Find oxidation state of chromium in CrO2Cl2CrO_2Cl_2CrO2​Cl2​

Let the oxidation state of chromium be xxx.

  • Oxygen usually has oxidation state −2-2−2
  • Chlorine in chlorides has oxidation state −1-1−1

Since the molecule is neutral:

x+2(−2)+2(−1)=0x + 2(-2) + 2(-1) = 0x+2(−2)+2(−1)=0 x−4−2=0x - 4 - 2 = 0x−4−2=0 x−6=0x - 6 = 0x−6=0 x=+6x = +6x=+6
  1. Final answer

The oxidation state of chromium in the product is:

6\boxed{6}6​
  1. Comparison with stored correct answer

Stored correct answer = 666

Derived answer = 666

Hence, the derived answer agrees with the stored correct answer.

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