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Redox Reactions question

2023 · 8 Apr · Shift 2 · Q20
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Redox Reactions question

2023 · 8 Apr · Shift 2 · Q20

JEE MainChemistryRedox ReactionsNumerical+4 / −1
The sum of oxidation state of the metals in Fe(CO)5,VO2+\mathrm{Fe}(\mathrm{CO})_{5}, \mathrm{VO}^{2+}Fe(CO)5​,VO2+ and WO3\mathrm{WO}_{3}WO3​ is ‾\underline{\hspace{2cm}}​.
Numerical answer
View written solutionFree

Correct answer: 10

  1. We need the oxidation state of the metal in each species:

    • Fe(CO)5\mathrm{Fe(CO)_5}Fe(CO)5​
    • VO2+\mathrm{VO^{2+}}VO2+
    • WO3\mathrm{WO_3}WO3​
  2. For Fe(CO)5\mathrm{Fe(CO)_5}Fe(CO)5​:

    • Carbon monoxide, CO\mathrm{CO}CO, is a neutral ligand.
    • Total charge on the complex is 000.
    • Let oxidation state of Fe be xxx. x+5(0)=0x + 5(0) = 0x+5(0)=0 x=0x = 0x=0 So, oxidation state of Fe is 000.
  3. For VO2+\mathrm{VO^{2+}}VO2+:

    • Oxygen usually has oxidation state −2-2−2.
    • Overall charge is +2+2+2.
    • Let oxidation state of V be xxx. x+(−2)=+2x + (-2) = +2x+(−2)=+2 x=+4x = +4x=+4 So, oxidation state of V is +4+4+4.
  4. For WO3\mathrm{WO_3}WO3​:

    • Oxygen has oxidation state −2-2−2.
    • Let oxidation state of W be xxx. x+3(−2)=0x + 3(-2) = 0x+3(−2)=0 x−6=0x - 6 = 0x−6=0 x=+6x = +6x=+6 So, oxidation state of W is +6+6+6.
  5. Sum of oxidation states of the metals: 0+4+6=100 + 4 + 6 = 100+4+6=10

Therefore, the required integer answer is 101010.

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