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Redox Reactions question

2021 · 16 Mar · Shift 2 · Q14
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Redox Reactions question

2021 · 16 Mar · Shift 2 · Q14

JEE MainChemistryRedox ReactionsMCQ+4 / −1
Statement I : Sodium hydride can be used as an oxidising agent. Statement II : The lone pair of electrons on nitrogen in pyridine makes it basic. Choose the CORRECT answer from the options given below :
  1. A
    Statement I is false but statement II is true
  2. B
    Both statement I and statement II are true
  3. C
    Statement I is true but statement II is false
  4. D
    Both statement I and statement II are false
View written solutionFree

Correct answer: A

  1. Analyze Statement I: "Sodium hydride can be used as an oxidising agent."

    Sodium hydride is NaH\text{NaH}NaH, which contains the hydride ion H−\text{H}^-H−. The hydride ion is a strong reducing agent, not an oxidising agent, because it readily donates electron density / hydride to other species.

    For example, NaH\text{NaH}NaH is commonly used as a strong base and reducing species in reactions.

    Therefore, Statement I is false.

  2. Analyze Statement II: "The lone pair of electrons on nitrogen in pyridine makes it basic."

    In pyridine, the nitrogen atom is sp2sp^2sp2 hybridised. One lone pair is present on nitrogen in an sp2sp^2sp2 orbital, and this lone pair is not involved in the aromatic sextet.

    Since this lone pair is available for donation to a proton, pyridine behaves as a base.

    Therefore, Statement II is true.

  3. Choose the correct option:

    • Statement I: False
    • Statement II: True

    Hence, the correct option is A: Statement I is false but statement II is true.

  4. Comparison with stored answer:

    Stored correct answer = A

    My derived answer = A

    So, they agree.

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