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Redox Reactions question

2021 · 18 Mar · Shift 2 · Q10

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Redox Reactions
2021 · 18 Mar · Shift 2 · Q10

Redox Reactions question

2021 · 18 Mar · Shift 2 · Q10

JEE MainChemistryRedox ReactionsMCQ+4 / −1

The oxidation states of nitrogen in

NO

,

NO_2

,

N_2O

and NO

_3^ -

are in the order of :

A
$N_2O$ > $NO_2$ > $NO$ > NO $_3^ -$
B
$NO$ > $NO_2$ > $N_2O$ > NO $_3^ -$
C
$NO_2$ > NO $_3^ -$ > $NO$ > $N_2O$
D
NO $_3^ -$ > $NO_2$ > $NO$ > $N_2O$

View written solutionFree

Correct answer: D

Find oxidation state of nitrogen in each species

Use the rule: oxygen usually has oxidation state $-2$ .

For $NO$

Let oxidation state of nitrogen be $x$ .

$x + (-2) = 0$ $x = +2$

So, in $NO$ , nitrogen is $+2$ .

For $NO_2$

Let oxidation state of nitrogen be $x$ .

$x + 2(-2) = 0$ $x - 4 = 0$ $x = +4$

So, in $NO_2$ , nitrogen is $+4$ .

For $N_2O$

Let average oxidation state of nitrogen be $x$ .

$2x + (-2) = 0$ $2x = +2$ $x = +1$

So, in $N_2O$ , the average oxidation state of nitrogen is $+1$ .

For $NO_3^-$

Let oxidation state of nitrogen be $x$ .

$x + 3(-2) = -1$ $x - 6 = -1$ $x = +5$

So, in $NO_3^-$ , nitrogen is $+5$ .

Arrange in decreasing order

We have:

$NO_3^- : +5$
$NO_2 : +4$
$NO : +2$
$N_2O : +1$

Therefore, the order is:

$NO_3^- > NO_2 > NO > N_2O$

This corresponds to Option D.

Comparison with stored answer

Stored correct answer: D

Derived answer: D

So, the derived answer agrees with the stored answer.

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