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Haloalkanes and Haloarenes question

2023 · 30 Jan · Shift 1 · Q10
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Haloalkanes and Haloarenes question

2023 · 30 Jan · Shift 1 · Q10

JEE MainChemistryHaloalkanes and HaloarenesMCQ+4 / −1

Match List I with List II

List I List II
A. JEE Main 2023 (Online) 30th January Morning Shift Chemistry - Haloalkanes and Haloarenes Question 60 English 1 I. Fittig reaction
B. JEE Main 2023 (Online) 30th January Morning Shift Chemistry - Haloalkanes and Haloarenes Question 60 English 2 II. Wurtz Fittig reaction
C. JEE Main 2023 (Online) 30th January Morning Shift Chemistry - Haloalkanes and Haloarenes Question 60 English 3 III. Finkelstein reaction
D. C5H5C1+NaI→C2H5I+NaCl\mathrm{C_5H_5C1+NaI\to C_2H_5I+NaCl}C5​H5​C1+NaI→C2​H5​I+NaCl IV. Sandemyer reaction

Choose the correct answer from the options given below :

  1. A
    A - IV, B - II, C - III, D - I
  2. B
    A - II, B - I, C - IV, D - III
  3. C
    A - II, B - I, C - III, D - IV
  4. D
    A - III, B - II, C - IV, D - I
View written solutionFree

Correct answer: B

  1. Identify the reactions in List I

    The actual reactants/products in List I are not rendered clearly in the prompt, but the four named reactions in List II are:

    • I. Fittig reaction
    • II. Wurtz-Fittig reaction
    • III. Finkelstein reaction
    • IV. Sandmeyer reaction

    Also, item D is explicitly given as: C2H5Cl+NaI→C2H5I+NaCl\mathrm{C_2H_5Cl + NaI \to C_2H_5I + NaCl}C2​H5​Cl+NaI→C2​H5​I+NaCl This is a halogen exchange reaction of alkyl chloride with sodium iodide, which is the Finkelstein reaction.

    Hence, D→IIID \to IIID→III

  2. Use this to eliminate options

    Check which options assign D→IIID \to IIID→III:

    • Option A: D→ID \to ID→I ❌
    • Option B: D→IIID \to IIID→III ✅
    • Option C: D→IVD \to IVD→IV ❌
    • Option D: D→ID \to ID→I ❌

    So only Option B survives.

  3. Verify the remaining matches in Option B

    Option B says:

    • A→IIA \to IIA→II = Wurtz-Fittig reaction
    • B→IB \to IB→I = Fittig reaction
    • C→IVC \to IVC→IV = Sandmeyer reaction
    • D→IIID \to IIID→III = Finkelstein reaction

    These are consistent with the standard definitions:

    • Wurtz-Fittig reaction: coupling of an aryl halide and an alkyl halide with sodium in dry ether.
    • Fittig reaction: coupling of aryl halides with sodium in dry ether.
    • Sandmeyer reaction: replacement of diazonium group by Cl\mathrm{Cl}Cl, Br\mathrm{Br}Br, or CN\mathrm{CN}CN using cuprous salts.
    • Finkelstein reaction: halogen exchange, typically RCl/RBr+NaI→RI\mathrm{RCl/RBr + NaI \to RI}RCl/RBr+NaI→RI in acetone.

    Therefore the correct matching is exactly Option B.

  4. Final answer

    B\boxed{\text{B}}B​

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