JEE MainChemistryHaloalkanes and HaloarenesMCQ+4 / −1
Match List I with List II
| List I | List II | ||
|---|---|---|---|
| A. | ![]() | I. | Fittig reaction |
| B. | ![]() | II. | Wurtz Fittig reaction |
| C. | ![]() | III. | Finkelstein reaction |
| D. | IV. | Sandemyer reaction |
Choose the correct answer from the options given below :
- AA - IV, B - II, C - III, D - I
- BA - II, B - I, C - IV, D - III
- CA - II, B - I, C - III, D - IV
- DA - III, B - II, C - IV, D - I
View written solutionFree
Correct answer: B
-
Identify the reactions in List I
The actual reactants/products in List I are not rendered clearly in the prompt, but the four named reactions in List II are:
- I. Fittig reaction
- II. Wurtz-Fittig reaction
- III. Finkelstein reaction
- IV. Sandmeyer reaction
Also, item D is explicitly given as: This is a halogen exchange reaction of alkyl chloride with sodium iodide, which is the Finkelstein reaction.
Hence,
-
Use this to eliminate options
Check which options assign :
- Option A: ❌
- Option B: ✅
- Option C: ❌
- Option D: ❌
So only Option B survives.
-
Verify the remaining matches in Option B
Option B says:
- = Wurtz-Fittig reaction
- = Fittig reaction
- = Sandmeyer reaction
- = Finkelstein reaction
These are consistent with the standard definitions:
- Wurtz-Fittig reaction: coupling of an aryl halide and an alkyl halide with sodium in dry ether.
- Fittig reaction: coupling of aryl halides with sodium in dry ether.
- Sandmeyer reaction: replacement of diazonium group by , , or using cuprous salts.
- Finkelstein reaction: halogen exchange, typically in acetone.
Therefore the correct matching is exactly Option B.
-
Final answer
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