Sign in
12thPass logo
New chatPYQ LibraryDoubtsRank report
Sign in to see Recents

Your guest activity stays on this device

Sign in to save progress →
Sign in

Electrochemistry question

2021 · 27 Aug · Shift 2 · Q18
Guest · filters and generic practice availableBrowsing as a guest · PYQ filters and generic practice are available. Sign in only for personalised features and saved progress.
  1. PYQ Library
  2. /JEE Main
  3. /Chemistry
  4. /Electrochemistry
  5. /2021 · 27 Aug · Shift 2 · Q18

Electrochemistry question

2021 · 27 Aug · Shift 2 · Q18

JEE MainChemistryElectrochemistryNumerical+4 / −1
The resistance of a conductivity cell with cell constant 1.14 cm −-− 1, containing 0.001 M KCl at 298 K is 1500 Ω\OmegaΩ. The molar conductivity of 0.001 M KCl solution at 298 K in S cm2 mol −-− 1 is ‾\underline{\hspace{2cm}}​. (Integer answer)
Numerical answer
View written solutionFree

Correct answer: 760

  1. Given data

    • Cell constant: lA=1.14 cm−1\dfrac{l}{A} = 1.14\ \text{cm}^{-1}Al​=1.14 cm−1
    • Resistance: R=1500 ΩR = 1500\ \OmegaR=1500 Ω
    • Concentration: C=0.001 MC = 0.001\ \text{M}C=0.001 M

  2. Find conductivity κ\kappaκ

    We use κ=cell constantR\kappa = \frac{\text{cell constant}}{R}κ=Rcell constant​

    So, κ=1.141500 S cm−1\kappa = \frac{1.14}{1500}\ \text{S cm}^{-1}κ=15001.14​ S cm−1

    κ=0.00076 S cm−1=7.6×10−4 S cm−1\kappa = 0.00076\ \text{S cm}^{-1} = 7.6 \times 10^{-4}\ \text{S cm}^{-1}κ=0.00076 S cm−1=7.6×10−4 S cm−1

  3. Use relation between molar conductivity and conductivity

    Molar conductivity is Λm=κ×1000C\Lambda_m = \kappa \times \frac{1000}{C}Λm​=κ×C1000​ where CCC is in mol L−1^{-1}−1.

    Substituting: Λm=7.6×10−4×10000.001\Lambda_m = 7.6\times 10^{-4} \times \frac{1000}{0.001}Λm​=7.6×10−4×0.0011000​

    Λm=7.6×10−4×106\Lambda_m = 7.6\times 10^{-4} \times 10^6Λm​=7.6×10−4×106

    Λm=760 S cm2 mol−1\Lambda_m = 760\ \text{S cm}^2\text{ mol}^{-1}Λm​=760 S cm2 mol−1

  4. Final integer answer

    760\boxed{760}760​

  5. Comparison with stored correct answer

    Stored correct answer = 760760760

    This matches the derived answer.

PreviousNext

More from Electrochemistry

  • The conductivity of a weak acid HA of concentration 0.001 mol L − 1 is 2.0 × 10 − 5 S cm − 1. If Λmo​(HA) = 190 S cm2 mol − 1, the ionization constant (Ka) of HA is equal to ​× 10 −…2021 · Numerical
  • For the cell Cu(s) | Cu2+ (aq) (0.1 M) || Ag+(aq) (0.01 M) | Ag(s) the cell potential E1 = 0.3095 V For the cell Cu(s) | Cu2+ (aq) (0.01 M) || Ag+(aq) (0.001 M) | Ag(s) the cell potential = ​×…2021 · Numerical
  • Consider the following cell reaction : Cd(s)​+Hg2​SO4(s)​+59​H2​O(l)​⇌ CdSO4​.59​H2​O(s)​+2Hg(l)​ The value of Ecell0​ is 4.315 V at 25 ∘ C. If Δ H…2021 · Numerical
  • Match List - I with List - II Choose the most appropriate answer from the options given below : Includes table2021 · MCQ
  • The Gibbs change (in J) for the given reaction at [Cu2+] = [Sn2+] = 1 M and 298K is : Cu(s) + Sn2+(aq.) → Cu2+(aq.) + Sn(s); (ESn2+∣Sn0​=−0.16V, ECu2+∣Cu0​=0.34V) Take F = 96500…2020 · Numerical
  • For the disproportionation reaction 2Cu+(aq) ⇌ Cu(s) + Cu2+(aq) at 298 K. ln K (where K is the equilibrium constant) is ​ × 10–1. Given : (ECu2+/Cu+0​=0.16VECu+/Cu0​=0.52VFRT​=0.025…2020 · Numerical
  • Let CNaCl and CBaSO4​ be the conductances (in S) measured for saturated aqueous solutions of NaCl and BaSO4​, respectively, at a temperature T. Which of the following is false?2020 · MCQ
  • The photoelectric current from Na (Work function, w0 = 2.3 eV) is stopped by the output voltage of the cell Pt(s) | H2​ (g, 1 Bar) | HCl (aq., pH =1) | AgCl(s) | Ag(s). The pH of aq. HCl required to stop the photoelectric current…2020 · Numerical