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Electrochemistry question

2021 · 31 Aug · Shift 2 · Q5
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  5. /2021 · 31 Aug · Shift 2 · Q5

Electrochemistry question

2021 · 31 Aug · Shift 2 · Q5

JEE MainChemistryElectrochemistryMCQ+4 / −1
Match List - I with List - II

List - I
(Parmeter)
List - II
(Unit)
(a) Cell constant (i) S cm2mol−1S\,c{m^2}mo{l^{ - 1}}Scm2mol−1
(b) Molar conductivity (ii) Dimensionless
(c) Conductivity (iii) m−1{m^{ - 1}}m−1
(d) Degree of dissociation of electrolyte (iv) Ω−1m−1{\Omega ^{ - 1}}{m^{ - 1}}Ω−1m−1


Choose the most appropriate answer from the options given below :
  1. A
    (a)-(iii), (b)-(i), (c)-(iv), (d)-(ii)
  2. B
    (a)-(iii), (b)-(i), (c)-(ii), (d)-(iv)
  3. C
    (a)-(i), (b)-(iv), (c)-(iii), (d)-(ii)
  4. D
    (a)-(ii), (b)-(i), (c)-(iii), (d)-(iv)
View written solutionFree

Correct answer: A

  1. Identify each physical quantity and its unit

We match each parameter in List-I with the correct unit in List-II.


  1. (a) Cell constant

Cell constant is defined as:

Cell constant=lA\text{Cell constant} = \frac{l}{A}Cell constant=Al​

where lll is distance between electrodes and AAA is area of cross-section.

So its unit is:

lengtharea=mm2=m−1\frac{\text{length}}{\text{area}} = \frac{m}{m^2} = m^{-1}arealength​=m2m​=m−1

Thus,

(a)→(iii)(a) \to (iii)(a)→(iii)
  1. (b) Molar conductivity

Molar conductivity Λm\Lambda_mΛm​ has units:

S cm2 mol−1S\,cm^2\,mol^{-1}Scm2mol−1

(or equivalently S m2 mol−1S\,m^2\,mol^{-1}Sm2mol−1 in SI form)

From the list, this corresponds to:

(b)→(i)(b) \to (i)(b)→(i)
  1. (c) Conductivity

Conductivity κ\kappaκ has SI unit:

Ω−1m−1\Omega^{-1} m^{-1}Ω−1m−1

Thus,

(c)→(iv)(c) \to (iv)(c)→(iv)
  1. (d) Degree of dissociation of electrolyte

Degree of dissociation α\alphaα is a ratio:

α=number dissociatedtotal number initially present\alpha = \frac{\text{number dissociated}}{\text{total number initially present}}α=total number initially presentnumber dissociated​

So it has no unit, i.e. it is dimensionless.

Thus,

(d)→(ii)(d) \to (ii)(d)→(ii)
  1. Final matching

The correct matching is:

(a)−(iii),(b)−(i),(c)−(iv),(d)−(ii)(a)-(iii),\quad (b)-(i),\quad (c)-(iv),\quad (d)-(ii)(a)−(iii),(b)−(i),(c)−(iv),(d)−(ii)

This corresponds to Option A.


  1. Comparison with stored answer

Stored correct answer: A

Derived answer: A

So, the derived answer agrees with the stored correct answer.

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